backwards number lookup

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There are 15 numbers that are stored in an array from large to small, using the binary lookup method to find out that the number is the value of the first element of the array, and if the number is not in the array, the output "no this number"

//July 22, 2017#include #defineLEN 15intMain () {intN; voidBinsearch (int* p,intN); intarr[len]={98, the, the, the, the, -, $, Wu, +, the, the, $, *, to, in}; printf ("Please enter the number you want to find: \ n"); scanf ("%d",N); Binsearch (Arr,n); return 0;}voidBinsearch (int* p,intN) { intLow,high,mid; Low=0; High=len-1; while(lowHigh ) {Mid= (Low+high)/2; if(p[mid]==N) {printf ("%d is the value of the%d element of the array (subscript sta

The offer--of the Sword 38: Number of occurrences of the number in the sorted array (using two-point lookup to find the first and last position)

Topic:Counts the number of occurrences of a number in a sorted array.Ideas:Because it is a well-ordered array, a binary lookup algorithm can be used.Generally the most easily thought of the idea is to use a binary search to find a first, and then go to his left and right side of the traverse, but this method because in the N array may also have n K, soThe complex

(algorithm: Binary lookup) in a sorted array, to find out the number of occurrences of a given number

Topic:In the sorted array, find out the number of occurrences of a given numberIdeas:Since there is a sort array, it is easy to think of binary lookups, with time complexity O (LOGN);First, by binary find the leftmost occurrence of the number of the subscript left (if not found, then return-1), and then through the binary search find the rightmost occurrence of the numb

Algorithm-Number of times the number appears in the sorted array _ two-point lookup

Topic:To count the number of occurrences of a number in a sorted array, such as the sort array {1,2,3,3,3,4,5}, the number 3 appears is 3. Ideas for solving problems:1. First of all, traversing an array is sure to know the number of a number, at this time the complexity O (n

The number of times a Linux lookup keyword appears in PHP

Find Clevercode in the current directory and subdirectories, all PHP occurrences are greater than 0 times.# find-type f-name ' *.php ' | Xargs grep clevercode./*.php-rc | Awk-f ': ' $ > 0 {print $1,$2} ' | Grep-v '/.svn/' | Sort-n-K 2-r1) find-type f-name ' *.php '. Finds all PHP files in the current directory and subdirectories.2) xargs grep clevercode./*.php-rc. Finds the Clevercode keyword in each file and displays the number of occurrences.3) awk-

The number of strings containing substrings in the Java lookup string implements code _java

1. Using the IndexOf method: public class Test11 { private static int counter = 0; /** * @param args * /public static void main (string[] args) { String str = "Sdss**hgjhadhcasch ^^ "; int i = stringnumbers (str); System.out.println (i); } public static int stringnumbers (String str) { if (str.indexof ("Java") ==-1) {return 0; } else if (Str.indexof ("Java")!=-1) { counter++; Stringnumbers (Str.substring (Str.indexof ("Java") +4)); return counter

The same number in the Java lookup string as the specified string

public class Employeedemo {//Method one: public int search (string str,string strres) {//lookup string in the same number as the specified string int n=0;//counter//for (int i = 0;i  The same number in the Java lookup string as the specified string

Array lookup element First occurrence index number

in the arrayTwo clear:return value type: intParameter list: int[] arr,int value*/ Public Static intGetIndex (int[] arr,intvalue) { //iterate through the array, get each element in the array, and compare the known data for(intx=0; x) { if(Arr[x] = =value) { //returns the current index value if it is equal. returnx; } } //The current code has a small problem//That is, if the data I am looking for does not exist in

The name of the document where the Linux lookup string is located and the line number example

For example, to find the AAA string in the ABC catalogue. Grep-rn "AAA"/wwwroot/abc/the current directory. -R indicates recursive lookup-n for displaying line numbers VI How the open document displays line numbers Set:number Do not show line numbers Set:nonumber Jumps to a specified number of lines, such as 100 lines Enter 100G carriage return Example Find "hello,world!" String, you can do this:

Linux grep (the number of times the Linux lookup keyword appeared in PHP)

Find Clevercode in the current directory and subdirectories, all PHP occurrences are greater than 0 times.# find-type f-name ' *.php ' | Xargs grep clevercode./*.php-rc | Awk-f ': ' $ > 0 {print $1,$2} ' | Grep-v '/.svn/' | Sort-n-K 2-r1) find-type f-name ' *.php '. Finds all PHP files in the current directory and subdirectories.2) xargs grep clevercode./*.php-rc. Finds the Clevercode keyword in each file and displays the number of occurrences.3) awk-

The number of files under the Java Lookup folder.

Example one, find Java type file Packagefile;ImportJava.io.File; Public classJava { Public Static intnum = 0; Public Static voidMain (string[] args) {//TODO auto-generated Method StubFile File =NewFile ("F:\\crt"); Show (file); System.out.println ("+num+" with "Jar file"); } Public Static voidShow (file file) {//TODO auto-generated Method Stub for(File f:file.listfiles ()) {if(F.isfile ()) {if(F.getname (). EndsWith (". dll") ) {num++; } }Else{show (f); }

Java lookup string1 and string2 are not the same letter type and number (string1 is string2 re-composition)

ImportJava.util.*; Public classSame { Public BooleanChecksam (String Stringa, String stringb) {//Write code here int[] str1=New int[256]; int[] str2=New int[256]; if(Stringa.length ()! =stringb.length ()) { return false; } for(intI=0;i) {Str1[stringa.charat (i)]++; Str2[stringb.charat (i)]++; } for(intj=0;j){ if(str1[j]!=Str2[j]) { return false; } } return true; }}Note the points:1. You can use ToCharArray () and Str.chara

The MongoDB process number lookup

For monitoring needs, you must call MongoDB's PID,Method 1:Add in the interactive file, pidfilepath=/var/run/mongodb.pid, restart MongoDB,Note that 2.5.3 below the version, the PID file is not found, this is a bug, in 2.5.3 or more versions before repair;Method 2: write the script to get it: the main content of the scriptPid= ' PS aux|grep mongodb |awk ' {print $} ' |sed-n ' 1p 'Method 3: inadvertently go to the data directory of MongoDB, found a mongod.lock, the inside record is PIDThen make a

Top K maximum number based on fast sort lookup

quicksearch function that has the largest number of K before it is quickly found.finding the number of K-large based on the idea of fast sortingfunctionQuickSearch (a,left,right,k) {if(kreturn-1;//Focus 1, when the value of K does not meet the requirements, return-1 if(Left==right)returnA[left];//Focus 2, the end condition of the recursionLet Key=-1,len=0; if(leftRight ) {Key=partition (A,left,right); L

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